Solving
a linear equation in one variable means finding the value of the variable that makes the equation true. For example, 11 is
the SOLUTION of x - 7 = 4, since 11 - 7 = 4. The number 11 is said to SATISFY the equation. Basically, the operation used
in solving equations is to manipulate both members, by addition, subtraction, multiplication, or division until the value
of the variable becomes apparent. This manipulation may be accomplished in a straightforward manner by use of the axioms outlined
in chapter 3 of this course. These axioms may be summed up in the following rule: If both members of an equation are increased,
decreased, multiplied, or divided by the same number, or by equal numbers, the results will be equal. (Division by zero is
excluded.)

As mentioned
earlier, an equation may be compared to a balance. What is done to one member must also be done to the other to maintain a
balance. An equation must always be kept in balance or the equality is lost. We use the above rule to remove or adjust terms
and coefficients until the value of the variable is discovered. Some examples of equations solved by means of the four operations
mentioned in the rule are given in the following paragraphs.

ADDITION

Find the
value of x in the equation

x-3=12

As in any
equation, we must isolate the variable on either the right or left side. In this problem, we leave the variable on the left
and perform the following steps:

1. Add 3
to both members of the equation, as follows:

x - 3 + 3 = 12 + 3

In effect,
we are "undoing" the subtraction indicated by the expression x - 3, for the purpose of isolating x in the left member.

2. Combining
terms, we have

x = 15

SUBTRACTION

Find the
value of x in the equation

x + 14 = 24

1. Subtract
14 from each member. In effect, this undoes the addition indicated in the expression x + 14.

x + 14 - 14 = 24 - 14

2. Combining
terms, we have

x = 10

MULTIPLICATION

Find the
value of y in the equation

y/5 = 10

1. The only
way to remove the 5 so that the y can be isolated is to undo the indicated division. Thus we use the inverse of division,
which is multiplication. Multiplying both members by 5, we have the following:

5(y/5) = 5(10)

2. Performing
the indicated multiplications, we have

y = 50

DIVISION

Find the
value of x in the equation

3x = 15
.

1. The multiplier
3 may be removed from the x by dividing the left member by 3. This must be balanced by dividing the right member by 3 also,
as follows:

2. Performing
the indicated divisions, we have

x=5